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面积 x+y=-3,x+9=y^2

解答

面积

x + y = - 3, x + 9 = y^{2}

解答

\frac{125}{6}

+1

十进制

20.83333 \dots

求解步骤

对于

x + y = - 3

将

y

移到一边:

y = - 3 - x

对于

x + 9 = y^{2}

将

y

移到一边:

y = x + 9, y = - x + 9

f_{1} (x) = - 3 - x

f_{2} (x) = x + 9

要找到相交点，解

f_{i} (x) = f_{j} (x)

- 3 - x = x + 9 : x = - 5

- 3 - x = - x + 9 : x = 0

x + 9 = - x + 9 : x = - 9

= \int_{- 9}^{- 5} ∣ f_{2} (x) - f_{3} (x) ∣ d x + \int_{- 5}^{0} ∣ f_{1} (x) - f_{3} (x) ∣ d x

= \int_{- 9}^{- 5} x + 9 - (- x + 9) d x + \int_{- 5}^{0} - 3 - x - (- x + 9) d x

\int_{- 9}^{- 5} x + 9 - (- x + 9) d x = \frac{32}{3}

\int_{- 5}^{0} - 3 - x - (- x + 9) d x = \frac{61}{6}

= \frac{32}{3} + \frac{61}{6}

化简

= \frac{125}{6}

作图

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