(\partial)/(\partial y)(ln(10x^2-7y^2))

解答

\frac{\partial}{\partial y} (ln (10 x^{2} - 7 y^{2}))

- \frac{14 y}{10 x ^{2} - 7 y ^{2}}

求解步骤

\frac{\partial}{\partial y} (ln (10 x^{2} - 7 y^{2}))

将

x

视为常数

使用连锁律:

\frac{1}{10 x ^{2} - 7 y ^{2}} \frac{\partial}{\partial y} (10 x^{2} - 7 y^{2})

= \frac{1}{10 x ^{2} - 7 y ^{2}} \frac{\partial}{\partial y} (10 x^{2} - 7 y^{2})

\frac{\partial}{\partial y} (10 x^{2} - 7 y^{2}) = - 14 y

= \frac{1}{10 x ^{2} - 7 y ^{2}} (- 14 y)

化简

\frac{1}{10 x ^{2} - 7 y ^{2}} (- 14 y) : - \frac{14 y}{10 x ^{2} - 7 y ^{2}}

= - \frac{14 y}{10 x ^{2} - 7 y ^{2}}

t an g e n t \frac{2}{3 3 x}

d er i v a t i v e f (x) = \frac{4 - 3 x - x ^{2}}{x ^{2} - 1}

\int 10 arcsin (x) d x

x \to - 2 lim ((x + 1) (x + 3))

d er i v a t i v e x^{(\frac{2}{x})}