(\partial)/(\partial y)(x+y-320)

Lösung

\frac{\partial}{\partial y} (x + y - 320)

1

Schritte zur Lösung

\frac{\partial}{\partial y} (x + y - 320)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (320)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (320) = 0

= 0 + 1 - 0

Vereinfache

= 1

\frac{\partial}{\partial x} (x^{4} + y^{3})

t a y l or \frac{1}{1 + x}, 0

n = 1 \sum \infty \frac{- 9 ^{n}}{n ^{4}}

\int (x^{2} + 2 x) \cdot 3^{x} d x

\int_{- 3}^{3} (13 - x^{2}) - (x^{2} - 5) d x