y^{''}-y^'-6y=0,y(0)=-2,y^'(0)=4

Lösung

y^{^{''}} - y^{^{'}} - 6 y = 0, y (0) = - 2, y^{^{'}} (0) = 4

y = - 2 e^{- 2 t}

Schritte zur Lösung

y^{''} (t) - y^{'} (t) - 6 y = 0

Solve linear ODE:

y = - 2 e^{- 2 t}

y = - 2 e^{- 2 t}

\frac{\partial}{\partial x} (3 x y + e^{- x^{2} y})

\int \frac{x}{2 e ^{x}} d x

d er i v a t i v e 6 x^{4} (7 - 6 x)^{3}

\frac{\partial}{\partial y} (sin^{4} (1 - 4 x y + y^{2}))

d er i v a t i v e f (x) = 500 - y - \frac{4 y}{y + 3}