integral from 1 to x of t^4

解答

\int_{1}^{x} t^{4} d t

\frac{x ^{5} - 1}{5}

求解步骤

\int_{1}^{x} t^{4} d t

使用幂法则

= [\frac{t ^{5}}{5}]_{1}^{x}

带入上下限计算后得:

\frac{x ^{5}}{5} - \frac{1}{5}

= \frac{x ^{5}}{5} - \frac{1}{5}

化简

= \frac{x ^{5} - 1}{5}

d er i v a t i v e f (x) = (x^{2} - 2)^{2}

\frac{d}{d x} (ln (3 x^{2} + 2 x))

x \to 0 + lim (csc (x) - cot (x))

n = 5 \sum \infty \frac{6}{n ^{2} - 1}

ma c l a u r in 5^{x}