y^'-4tan(2x)y=sin(2x)

Lösung

y^{^{'}} - 4 tan (2 x) y = sin (2 x)

y = - \frac{cos ( 2 x )}{6} + \frac{c _{1}}{cos ^{2} ( 2 x )}

Schritte zur Lösung

y^{'} (x) - 4 tan (2 x) y = sin (2 x)

Solve linear ODE:

y = - \frac{cos ( 2 x )}{6} + \frac{c _{1}}{cos ^{2} ( 2 x )}

y = - \frac{cos ( 2 x )}{6} + \frac{c _{1}}{cos ^{2} ( 2 x )}

\int_{0}^{1} \frac{24}{x ^{2} - 36} d x

\frac{d}{d x} (x + 8)

x \to 1 - lim (\frac{2 x + 5}{x + 1})

x \to 0 + lim (ln (\frac{1}{2 x}))

2 y^{^{''}} - y = 4 sin (3 t)