derivative f(x)=x+9/x

Lösung

ableitung von

f (x) = x + \frac{9}{x}

1 - \frac{9}{x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (x + \frac{9}{x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (\frac{9}{x})

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{9}{x}) = - \frac{9}{x ^{2}}

= 1 - \frac{9}{x ^{2}}

\frac{\partial}{\partial x} ((x y)^{z})

\int \frac{x ^{3} - x ^{2} - 4 x + 4}{x ^{3} - x ^{2} - 6 x} d x

\frac{\partial}{\partial x} (e^{2 y} cos (3 x))

in v erse l a pl a ce 3

y^{^{''}} - 5 y^{^{'}} + 6 y = x \cdot e^{(- 4 \cdot x)}