xy^'=y+6x^2sin(x),y(pi)=0

Lösung

x y^{^{'}} = y + 6 x^{2} sin (x), y (π) = 0

y = - 6 x cos (x) - 6 x

Schritte zur Lösung

x y^{'} (x) = y + 6 x^{2} sin (x)

Solve linear ODE:

y = - 6 x cos (x) - 6 x

y = - 6 x cos (x) - 6 x

x \to - 1 lim (x^{2} - 3 x - 4)

x \to 4 lim (\frac{3}{( x - 4 ) ^{2}})

\int cos^{4} (\frac{1}{2} x) d x

\int_{0}^{1} \frac{1}{2} x^{2} d x

d er i v a t i v e x - 5 - 100