(\partial)/(\partial x)(z^2cos(yx))

解答

\frac{\partial}{\partial x} (z^{2} cos (y x))

- z^{2} y sin (y x)

求解步骤

\frac{\partial}{\partial x} (z^{2} cos (y x))

将

z, y

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= z^{2} \frac{\partial}{\partial x} (cos (y x))

使用连锁律:

- sin (y x) \frac{\partial}{\partial x} (y x)

= - sin (y x) \frac{\partial}{\partial x} (y x)

\frac{\partial}{\partial x} (y x) = y

= z^{2} (- sin (y x) y)

化简

= - z^{2} y sin (y x)

y^{^{'}} - \frac{6}{x} y = \frac{( y ^{3} )}{x ^{4}}

\int_{4}^{9} x x d x

\int \frac{1}{x ^{2} x ^{2} - 196} d x

\int \frac{e ^{x} ( 2 x ^{3} + x ^{2} - 4 x - 6 )}{6 x ^{4}} d x

t \to 0 lim (\frac{sin ( 2 t )}{t})