What is the solution for y^'+3(tan(3x))y=7cos(3x) ?

The solution for y^'+3(tan(3x))y=7cos(3x) is y=(7x)/(sec(3x))+(c_{1})/(sec(3x))

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y^'+3(tan(3x))y=7cos(3x)

y^{^{'}} + 3 (tan (3 x)) y = 7 cos (3 x)

y = \frac{7 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

Solution steps

y^{'} (x) + 3 (tan (3 x)) y = 7 cos (3 x)

Solve linear ODE:

y = \frac{7 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

y = \frac{7 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

What is the solution for y^'+3(tan(3x))y=7cos(3x) ?
The solution for y^'+3(tan(3x))y=7cos(3x) is y=(7x)/(sec(3x))+(c_{1})/(sec(3x))