derivative of 3^x-2

解答

\frac{d}{d x} (3^{x} - 2)

ln (3) \cdot 3^{x}

求解步骤

\frac{d}{d x} (3^{x} - 2)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3^{x}) - \frac{d}{d x} (2)

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

\frac{d}{d x} (2) = 0

= 3^{x} ln (3) - 0

化简

= ln (3) \cdot 3^{x}

\frac{d}{d x} (e^{x^{2}} y)

\int \frac{1}{3} x^{2} d x

x \to 0 lim (x^{3} + x)

\int \frac{2}{( x ^{2} + 1 ) ^{\frac{3}{2}}} d x

\frac{d}{d x} (\frac{1 - 3 x}{2 x + 1})