limit as x approaches 2 of 2x^2+4x+a

解答

x \to 2 lim (2 x^{2} + 4 x + a)

a + 16

求解步骤

x \to 2 lim (2 x^{2} + 4 x + a)

代入值

x = 2

= 2 \cdot 2^{2} + 4 \cdot 2 + a

化简

2 \cdot 2^{2} + 4 \cdot 2 + a : a + 16

= a + 16

\int x 3 4 x + 1 d x

d er i v a t i v e \frac{3 ( 7 - x ) + 5 9 + x ^{2}}{15}

d er i v a t i v e \frac{x ^{2} - 2}{2 x + 1}

\int (\frac{1}{x ^{2} - 4}) d x

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2} + x})