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受欢迎的函数 >

y= 4/(cos(x))+1/(tan(x))

解答

y = \frac{4}{cos ( x )} + \frac{1}{tan ( x )}

解答

Period : 2 π

Domain : 2 πn < x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < π + 2 πn or π + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

Range : - \infty < f (x) < \infty

X 截距 : (arcsin (2 - 5) + 2 π + 2 πn, 0), (π + arcsin (- 2 + 5) + 2 πn, 0)

Asymptotes : 垂直 x = 2 πn, x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn, x = π + 2 πn

Extreme Points : 极小值 (0.59039 \dots + 2 πn, 6.30734 \dots), 极大值 (π - 0.59039 \dots + 2 πn, - 6.30734 \dots)

+1

间隔符号

Domain : (2 πn, \frac{π}{2} + 2 πn) \cup (\frac{π}{2} + 2 πn, π + 2 πn) \cup (π + 2 πn, \frac{3 π}{2} + 2 πn) \cup (\frac{3 π}{2} + 2 πn, 2 π + 2 πn)

Range : (- \infty, \infty)

求解步骤

\frac{4}{cos ( x )} + \frac{1}{tan ( x )}

的周期:

2 π

\frac{4}{cos ( x )} + \frac{1}{tan ( x )}

的定义域

: 2 πn < x < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < x < π + 2 πn or π + 2 πn < x < \frac{3 π}{2} + 2 πn or \frac{3 π}{2} + 2 πn < x < 2 π + 2 πn

\frac{4}{cos ( x )} + \frac{1}{tan ( x )}

的值域:

- \infty < f (x) < \infty

\frac{4}{cos ( x )} + \frac{1}{tan ( x )}

的轴截距点

:

X 截距

: (arcsin (2 - 5) + 2 π + 2 πn, 0), (π + arcsin (- 2 + 5) + 2 πn, 0)

\frac{4}{cos ( x )} + \frac{1}{tan ( x )}

的渐近线

:

垂直

: x = 2 πn, x = \frac{3 π}{2} + 2 πn, x = \frac{π}{2} + 2 πn, x = π + 2 πn

\frac{4}{cos ( x )} + \frac{1}{tan ( x )}

的极值点:

极小值

(0.59039 \dots + 2 πn, 6.30734 \dots),

极大值

(π - 0.59039 \dots + 2 πn, - 6.30734 \dots)

作图

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