invers-(-2x^3+4x)/(-6x+1/x)

Lösung

invers

- \frac{- 2 x ^{3} + 4 x}{- 6 x + \frac{1}{x}}

\frac{2 - 3 x + 9 x ^{2} - 10 x + 4}{2}, - \frac{2 - 3 x + 9 x ^{2} - 10 x + 4}{2}, \frac{2 - 3 x - 9 x ^{2} - 10 x + 4}{2}, - \frac{2 - 3 x - 9 x ^{2} - 10 x + 4}{2}

Schritte zur Lösung

y = - \frac{- 2 x ^{3} + 4 x}{- 6 x + \frac{1}{x}}

Ersetze

x

durch

y

x = - \frac{- 2 y ^{3} + 4 y}{- 6 y + \frac{1}{y}}

Löse nach

y, x = - \frac{- 2 y ^{3} + 4 y}{- 6 y + \frac{1}{y}}

\frac{2 - 3 x + 9 x ^{2} - 10 x + 4}{2}, - \frac{2 - 3 x + 9 x ^{2} - 10 x + 4}{2}, \frac{2 - 3 x - 9 x ^{2} - 10 x + 4}{2}, - \frac{2 - 3 x - 9 x ^{2} - 10 x + 4}{2}

in v erse 5 x - 7

in v erse f (x) = \frac{5 - 2 x}{4 x + 2}

in v erse f (x) = \frac{3 ^{x}}{3 + 3 ^{x}}

in v erse \frac{2}{x ^{2} - 2 x - 3}

in v erse f (x) = \frac{2 x - 4}{x - 3}