逆 f(x)=(2x(x+3))/((x-2)(x-5))

解

逆

f (x) = \frac{2 x ( x + 3 )}{( x - 2 ) ( x - 5 )}

\frac{7 x + 6 + 9 x ^{2} + 164 x + 36}{2 ( x - 2 )}, \frac{7 x + 6 - 9 x ^{2} + 164 x + 36}{2 ( x - 2 )}

解答ステップ

y = \frac{2 x ( x + 3 )}{( x - 2 ) ( x - 5 )}

x

を以下で置き換える:

y

x = \frac{2 y ( y + 3 )}{( y - 2 ) ( y - 5 )}

y

を解く

x = \frac{2 y ( y + 3 )}{( y - 2 ) ( y - 5 )}

\frac{7 x + 6 + 9 x ^{2} + 164 x + 36}{2 ( x - 2 )}, \frac{7 x + 6 - 9 x ^{2} + 164 x + 36}{2 ( x - 2 )}