extreme 6x^{2/3}-4x

Lösung

extrempunkte

6 x^{\frac{2}{3}} - 4 x

Minimum (1, 2)

Schritte zur Lösung

f^{'} (x) = \frac{4}{x ^{\frac{1}{3}}} - 4

Intervalle finden:

Absteigend

: - \infty < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = 1

6 x^{\frac{2}{3}} - 4 x : 2

Minimum (1, 2)

e x t re m e f (x) = 4 x^{2} + 2 y^{2} - 2 x y - 10 y - 2 x

e x t re m e f (x) = 2 x^{2} - 6 x^{4}

e x t re m e f (x) = - x^{2} + 10, - 3 \leq x \leq 4

e x t re m e \frac{2}{x + 5}

e x t re m e f (x) = - 3 x^{3} - \frac{63}{2} x^{2} - 90 x + 1