extreme f(x)=x^2+9x-9

Lösung

extrempunkte

f (x) = x^{2} + 9 x - 9

Minimum (- \frac{9}{2}, - \frac{117}{4})

Schritte zur Lösung

f^{'} (x) = 2 x + 9

Intervalle finden:

Absteigend

: - \infty < x < - \frac{9}{2},

Ansteigend

: - \frac{9}{2} < x < \infty

Stecke

x = - \frac{9}{2}

x^{2} + 9 x - 9 : - \frac{117}{4}

Minimum (- \frac{9}{2}, - \frac{117}{4})

e x t re m e f (x, y) = x^{2} + y^{2} - 4 x + 17 x - 10 y + 2021

e x t re m e f (x) = 18 x^{2} - 32 y^{2} - 36 x - 128 y - 110

e x t re m e f (x, y) = - 3 x y + x^{3} + y^{3}

e x t re m e f (x) = 16 - x^{2}, - 4 \leq x \leq 4

e x t re m e f (x) = 6 + 3 x - 3 x^{2}