extreme f(x)=(3-sqrt(9-x^2))/x

Lösung

extrempunkte

f (x) = \frac{3 - 9 - x ^{2}}{x}

Minimum (- 3, - 1), Maximum (3, 1)

Schritte zur Lösung

f^{'} (x) = \frac{x ^{2} - ( 3 - 9 - x ^{2} ) - ( x + 3 ) ( x - 3 )}{x ^{2} - ( x + 3 ) ( x - 3 )}

Intervalle finden:

Ansteigend

: - 3 < x < 0,

Ansteigend

: 0 < x < 3

Stecke

x = - 3

\frac{3 - 9 - x ^{2}}{x} : - 1

Minimum (- 3, - 1)

Stecke

x = 3

\frac{3 - 9 - x ^{2}}{x} : 1

Maximum (3, 1)

Minimum (- 3, - 1), Maximum (3, 1)

e x t re m e f (x) = 2 x^{3} + x y^{2} + 5 x^{2} + y^{2} + 4

e x t re m e 2 cos (3 x) + 2 sin (1 0^{\circ}) y + 3 x - 10 y = 0

e x t re m e f (x, y) = x y + y^{2}

e x t re m e f (x) = \frac{3}{7} (x^{2} - 1)^{\frac{2}{3}}

e x t re m e f (x, y) = x y + 2 x y^{2}