extreme f(x)=x^3-3x[0.3]

Lösung

extrempunkte

f (x) = x^{3} - 3 x [0.3]

Maximum (- \frac{3}{10}, 0.32863 \dots), Minimum (\frac{3}{10}, - 0.32863 \dots)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 0.9

Intervalle finden:

Ansteigend

: - \infty < x < - 0.54772 \dots,

Absteigend

: - 0.54772 \dots < x < 0.54772 \dots,

Ansteigend

: 0.54772 \dots < x < \infty

Stecke

x = - \frac{3}{10}

x^{3} - 3 x [0.3] : 0.32863 \dots

Maximum (- \frac{3}{10}, 0.32863 \dots)

Stecke

x = \frac{3}{10}

x^{3} - 3 x [0.3] : - 0.32863 \dots

Minimum (\frac{3}{10}, - 0.32863 \dots)

Maximum (- \frac{3}{10}, 0.32863 \dots), Minimum (\frac{3}{10}, - 0.32863 \dots)

e x t re m e f (x) = \frac{4860}{x} + 18 x + 731856

e x t re m e f (x) = 3 x^{2} + 4 x - 6

e x t re m e f (x, y) = (x - 3)^{2} - (y - 1)^{2}

e x t re m e f (x, y) = 7 e^{y} - 3 y e^{x}

e x t re m e \frac{1}{t ^{3} + 2}