extreme (x+1)(x+2)(x+3)(x+4)

Lösung

extrempunkte

(x + 1) (x + 2) (x + 3) (x + 4)

Minimum (\frac{- 5 - 5}{2}, - 1), Maximum (- \frac{5}{2}, \frac{9}{16}), Minimum (\frac{- 5 + 5}{2}, - 1)

Schritte zur Lösung

f^{'} (x) = 2 (2 x + 5) (x^{2} + 5 x + 5)

Intervalle finden:

Absteigend

: - \infty < x < \frac{- 5 - 5}{2},

Ansteigend

: \frac{- 5 - 5}{2} < x < - \frac{5}{2},

Absteigend

: - \frac{5}{2} < x < \frac{5 - 5}{2},

Ansteigend

: \frac{5 - 5}{2} < x < \infty

Stecke

x = \frac{- 5 - 5}{2}

(x + 1) (x + 2) (x + 3) (x + 4) : - 1

Minimum (\frac{- 5 - 5}{2}, - 1)

Stecke

x = - \frac{5}{2}

(x + 1) (x + 2) (x + 3) (x + 4) : \frac{9}{16}

Maximum (- \frac{5}{2}, \frac{9}{16})

Stecke

x = \frac{- 5 + 5}{2}

(x + 1) (x + 2) (x + 3) (x + 4) : - 1

Minimum (\frac{- 5 + 5}{2}, - 1)

Minimum (\frac{- 5 - 5}{2}, - 1), Maximum (- \frac{5}{2}, \frac{9}{16}), Minimum (\frac{- 5 + 5}{2}, - 1)

e x t re m e y = (\frac{1}{x ^{2} - 4 x - 5})

e x t re m e f (x) = 340 x^{2} + 4080 x^{3}, 0 \leq x \leq 0.08

e x t re m e y = - x^{2} - 6 x - 8

e x t re m e f (x) = x e^{- \frac{x ^{2}}{162}}

e x t re m e f (x, y) = x^{2} + 2 \cdot y^{2} + 4 \cdot x - 4 \cdot y