extreme (sqrt(x-5))/4

Lösung

extrempunkte

\frac{x - 5}{4}

Minimum (5, 0)

Schritte zur Lösung

f^{'} (x) = \frac{1}{8 x - 5}

Intervalle finden:

Ansteigend

: 5 < x < \infty

Stecke

x = 5

\frac{x - 5}{4} : 0

Minimum (5, 0)

e x t re m e f (x, y) = x^{2} + y^{2} - 18 x + 16 y - 7

e x t re m e f (x) = 7 x - 14 cos (x), - 2 \leq x \leq 0

e x t re m e f (x) = 3 x, - 27 \leq x \leq 27

e x t re m e f (t) = \frac{1}{9} [\frac{t ^{3}}{3} + \frac{3 t ^{2}}{2} - 28 t]

e x t re m e u (x, y) = (2 - x) (y - 1) + 2 (x - 2)^{2} + 2 (y - 1)^{2} - 3