extreme f(x)= 5/(x^2+1)-1

Lösung

extrempunkte

f (x) = \frac{5}{x ^{2} + 1} - 1

Maximum (0, 4)

Schritte zur Lösung

f^{'} (x) = - \frac{10 x}{( x ^{2} + 1 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < 0,

Absteigend

: 0 < x < \infty

Stecke

x = 0

\frac{5}{x ^{2} + 1} - 1 : 4

Maximum (0, 4)

e x t re m e 2 x^{3} + 6 x^{2} - 90 x + 7, - 5 \leq x \leq 6

e x t re m e f (x) = - \frac{5}{4} x^{2} + \frac{5}{2} x + \frac{7}{4}

e x t re m e f (x, y) = x + y - \frac{3}{2} (x^{2} + y^{2} + 1)

e x t re m e - x^{2} + 8 x - 9

e x t re m e f (x) = x^{3} - 12 x^{2} - 27 x + 2, 1 \leq x \leq 10