extreme f(x)=10000e^{0.17(x-1.62)^2}

Lösung

extrempunkte

f (x) = 10000 e^{0.17 (x - 1.62)^{2}}

Minimum (1.62, 10000)

Schritte zur Lösung

f^{'} (x) = 3400 e^{0.17 (x - 1.62)^{2}} (x - 1.62)

Intervalle finden:

Absteigend

: - \infty < x < 1.62,

Ansteigend

: 1.62 < x < \infty

Stecke

x = 1.62

10000 e^{0.17 (x - 1.62)^{2}} : 10000

Minimum (1.62, 10000)

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