What is the critical f(x)=(x^4-1)/(x^3) ?

The critical f(x)=(x^4-1)/(x^3) is None

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critical f(x)=(x^4-1)/(x^3)

critical points

f (x) = \frac{x ^{4} - 1}{x ^{3}}

None

Solution steps

\frac{x ^{4} - 1}{x ^{3}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{4} - 1}{x ^{3}} : x < 0 or x > 0

\frac{x ^{4} - 1}{x ^{3}}

is not defined at

x = 0

, therefore:

None

What is the critical f(x)=(x^4-1)/(x^3) ?
The critical f(x)=(x^4-1)/(x^3) is None