What is the domain of (sqrt(16-x^2))/(sqrt(x+2)) ?

The domain of (sqrt(16-x^2))/(sqrt(x+2)) is -2<x<= 4

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domain of (sqrt(16-x^2))/(sqrt(x+2))

domain

\frac{16 - x ^{2}}{x + 2}

- 2 < x \leq 4

Interval Notation

(- 2, 4]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 4

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

- 2 < x \leq 4

What is the domain of (sqrt(16-x^2))/(sqrt(x+2)) ?
The domain of (sqrt(16-x^2))/(sqrt(x+2)) is -2<x<= 4