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midpoint
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domain of f(x)=(|x|)/xasymptotes of (x^2+x-12)/(x-3)intercepts of (2x)/(x^2-1)range of f(x)=|x^2-4x|-1inverse of f(x)=\sqrt[5]{(x+3)/2}
Frequently Asked Questions (FAQ)
What is the midpoint (2,-8),(7,-4) ?
The midpoint (2,-8),(7,-4) is (9/2 ,-6)