What is the domain of f(x)=sqrt(9-t) ?

The domain of f(x)=sqrt(9-t) is t<= 9

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domain of f(x)=sqrt(9-t)

domain

f (x) = 9 - t

t \leq 9

Interval Notation

(- \infty, 9]

Solution steps

Find non-negative values for radicals:

t \leq 9

The function domain

t \leq 9

in t erce pt s f (x) = x^{2} + y - 4 = 0

d o main f (x) = \frac{2}{3} (x - 3)^{2} + 4

r an g e f (x) = 3 x + 4 - 2

e x t re m e f (x) = x^{3} + 3 x + 9

d o main f (x) = 2 - 2^{a r c t a n ((x - 1)^{2})}