extreme y=x^3-5x^2-8x+6

Lösung

extrempunkte

y = x^{3} - 5 x^{2} - 8 x + 6

Maximum (- \frac{2}{3}, \frac{238}{27}), Minimum (4, - 42)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 10 x - 8

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{2}{3},

Absteigend

: - \frac{2}{3} < x < 4,

Ansteigend

: 4 < x < \infty

Stecke

x = - \frac{2}{3}

x^{3} - 5 x^{2} - 8 x + 6 : \frac{238}{27}

Maximum (- \frac{2}{3}, \frac{238}{27})

Stecke

x = 4

x^{3} - 5 x^{2} - 8 x + 6 : - 42

Minimum (4, - 42)

Maximum (- \frac{2}{3}, \frac{238}{27}), Minimum (4, - 42)

p er i o d i c i t y f (x) = 2 sin (x - \frac{π}{3})

e x t re m e f (x) = \frac{e ^{x} - e ^{- x}}{9}

d o main f (x) = x^{2} - 12

a sy m pt o t es f (x) = \frac{( x ^{2} + 3 x - 10 )}{x ^{2} - 4}

r an g e f (x) = \frac{7}{x} - 2