monotone (2x-1)^7(x+5)^6

Lösung

monotone intervalle

(2 x - 1)^{7} (x + 5)^{6}

Ansteigend : - \infty < x < - 5, Absteigend : - 5 < x < - \frac{32}{13}, Ansteigend : - \frac{32}{13} < x < \frac{1}{2}, Ansteigend : \frac{1}{2} < x < \infty

Schritte zur Lösung

f^{'} (x) = 2 (x + 5)^{5} (2 x - 1)^{6} (13 x + 32)

Intervalle finden:

Ansteigend

: - \infty < x < - 5,

Absteigend

: - 5 < x < - \frac{32}{13},

Ansteigend

: - \frac{32}{13} < x < \frac{1}{2},

Ansteigend

: \frac{1}{2} < x < \infty

Ansteigend : - \infty < x < - 5, Absteigend : - 5 < x < - \frac{32}{13}, Ansteigend : - \frac{32}{13} < x < \frac{1}{2}, Ansteigend : \frac{1}{2} < x < \infty

in t erce pt s \frac{2 x + 1}{3 x ^{2}}

d o main f (x) = \frac{( x + 1 ) ^{2}}{2 x - 1}

s hi f t y = - 5 sin (π - 4 x) + 1

in v erse \frac{x + 4}{x - 5}

in t erce pt s f (x) = x^{2} - 4 x - 3