f(x)= 1/(1-x^2)-,1<x<1

Lösung

f (x) = \frac{1}{1 - x ^{2}} -, 1 < x < 1

Parity : Gerade

Inverse : - \frac{1 - x}{x}, - - \frac{1 - x}{x}

Schritte zur Lösung

Parity of

\frac{1}{1 - x ^{2}} -, 1 < x < 1 :

Gerade

Umkehrung von

\frac{1}{1 - x ^{2}} -, 1 < x < 1 : - \frac{1 - x}{x}, - - \frac{1 - x}{x}

y = 16 - x^{2}

f (x) = x^{2} - x + 12

f (x) = \frac{x + 1}{x ^{2} - 1}

f (x) = (x^{2} - 4)^{\frac{2}{3}}

f (x) = x^{2} - 6 x - 1