inflection (x^2-4)^2

Lösung

wendepunkte

(x^{2} - 4)^{2}

(- \frac{2}{3}, \frac{64}{9}), (\frac{2}{3}, \frac{64}{9})

Schritte zur Lösung

f^{''} (x) = 4 (3 x^{2} - 4)

Intervalle finden:

Konkav steigend

: - \infty < x < - \frac{2}{3},

Konkav fallend

: - \frac{2}{3} < x < \frac{2}{3},

Konkav steigend

: \frac{2}{3} < x < \infty

Stecke

x = - \frac{2}{3}

(x^{2} - 4)^{2} : \frac{64}{9}

(- \frac{2}{3}, \frac{64}{9})

Stecke

x = \frac{2}{3}

(x^{2} - 4)^{2} : \frac{64}{9}

(\frac{2}{3}, \frac{64}{9})

(- \frac{2}{3}, \frac{64}{9}), (\frac{2}{3}, \frac{64}{9})

d o main f (x) = - 3 x + 2 - 4

in v erse f (x) = g (x) = - 0.5 x

a sy m pt o t es f (x) = \frac{x ^{2} - x - 2}{x ^{2} + x - 6}

in v erse f (x) = 4 x^{5}

r an g e f (x) = 2 x