定义域 f(x)=(x-2)/(3x+5)

解答

定义域

f (x) = \frac{x - 2}{3 x + 5}

x < - \frac{5}{3} or x > - \frac{5}{3}

间隔符号

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

求解步骤

找到无定义的点（奇点）:

x = - \frac{5}{3}

函数定义域

x < - \frac{5}{3} or x > - \frac{5}{3}

d o main f (x) = 6 + \frac{40}{x}

in t erce pt s f (x) = - 5 x^{2} - 40 x - 77

in t erce pt s y = \frac{( - x - 2 )}{( 5 x + 3 )}

s l o p e in t erce pt x + 13 y = - 8

d o main \frac{1}{x + 8} + ln (\frac{1}{x} - \frac{1}{1 - x})