f(x)=tan^{38}(x^2)

解答

f (x) = tan^{38} (x^{2})

Parity : 偶

Inverse : arctan (38 x), - arctan (38 x), arctan (- 38 x), - arctan (- 38 x)

求解步骤

tan^{38} (x^{2})

的奇偶性:

偶

tan^{38} (x^{2})

的反函数:

arctan (38 x), - arctan (38 x), arctan (- 38 x), - arctan (- 38 x)

y = 7 + 4 tan (x)

f (x) = 31 x^{2} + 31 x + 38

p (x) = 3 x^{2} - 5 x + 1

y = \frac{10}{( x + 9 )}

f (5) = 2 x