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Beliebt Geometry >

fläche f(x)=x^2+1[-3,3]

Lösung

fläche

f (x) = x^{2} + 1 [- 3, 3]

Lösung

Unbeschr \overset{a}{¨} nkt

Schritte zur Lösung

y = x^{2} + 1 \cdot [- 3, 3]

Rewrite

y = x^{2} + 1 \cdot [- 3, 3]

in the standard form:

4 \cdot \frac{1}{4} (y - 1 \cdot [- 3, 3]) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 1 \cdot [- 3, 3]), p = \frac{1}{4}

Parabola's area is always unbounded

Unbeschr \overset{a}{¨} nkt

Beliebte Beispiele

fläche y=-3x^2+6x

a re a y = - 3 x^{2} + 6 x

fläche y=x^2-2x+1

a re a y = x^{2} - 2 x + 1

a re a - 3 x^{2}

fläche 2+y^2-6x+2y+1=0

a re a 2 + y^{2} - 6 x + 2 y + 1 = 0

fläche f(x)=x^2-6x

a re a f (x) = x^{2} - 6 x