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Beliebt Geometry >

2x^2+2y^2+x+y=0

Lösung

2 x^{2} + 2 y^{2} + x + y = 0

Lösung

(a, b) = (- \frac{1}{4}, - \frac{1}{4}), r = \frac{1}{2 2}

Schritte zur Lösung

2 x^{2} + 2 y^{2} + x + y = 0

Rewrite

2 x^{2} + 2 y^{2} + x + y = 0

in the form of the standard circle equation

(x - (- \frac{1}{4}))^{2} + (y - (- \frac{1}{4}))^{2} = (\frac{1}{2 2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{4}, - \frac{1}{4}), r = \frac{1}{2 2}

Graph

Beliebte Beispiele

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