x^2+y^2-5x=0

解答

x^{2} + y^{2} - 5 x = 0

(a, b) = (\frac{5}{2}, 0), r = \frac{5}{2}

求解步骤

x^{2} + y^{2} - 5 x = 0

将

x^{2} + y^{2} - 5 x = 0

改写为圆标准方程

(x - \frac{5}{2})^{2} + (y - 0)^{2} = (\frac{5}{2})^{2}

因此圆的性质是:

(a, b) = (\frac{5}{2}, 0), r = \frac{5}{2}

2 x^{2} + 2 y^{2} - 2 x - 6 y - 13 = 0

(x^{2} + 4 x + 4) + (y^{2} - 8 y + 16) = - 9 + 4 + 16

(x - 20)^{2} + (y - 0.05)^{2} = 81

2 x^{2} + 2 y^{2} - 2 x + 18 y + 33 = 0

(x - 3)^{2} + (y + 4)^{2} = 2