x^2+y^2+4x-10y=4

解答

x^{2} + y^{2} + 4 x - 10 y = 4

(a, b) = (- 2, 5), r = 33

求解步骤

x^{2} + y^{2} + 4 x - 10 y = 4

将

x^{2} + y^{2} + 4 x - 10 y = 4

改写为圆标准方程

(x - (- 2))^{2} + (y - 5)^{2} = (33)^{2}

因此圆的性质是:

(a, b) = (- 2, 5), r = 33

(- x + 3)^{2} + (- y + 2)^{2} = 2^{2}

x^{2} + y^{2} - x - 4 y + 4 = 0

p^{2} + q^{2} = 170

x^{2} + y^{2} - 8 x - 2 y + 11 = 0

(x + 4)^{2} + (y - 1)^{2} = 8