8x^2+4x=7y

Lösung

8 x^{2} + 4 x = 7 y

(h, k) = (- \frac{1}{4}, - \frac{1}{14}), p = \frac{7}{32}

Schritte zur Lösung

8 x^{2} + 4 x = 7 y

Rewrite

8 x^{2} + 4 x = 7 y

in the standard form

4 \cdot \frac{7}{32} (y - (- \frac{1}{14})) = (x - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, - \frac{1}{14}), p = \frac{7}{32}