16x^2+16y^2+19x-40y=315

解

16 x^{2} + 16 y^{2} + 19 x - 40 y = 315

(a, b) = (- \frac{19}{32}, \frac{5}{4}), r = \frac{22121}{32}

解答ステップ

16 x^{2} + 16 y^{2} + 19 x - 40 y = 315

16 x^{2} + 16 y^{2} + 19 x - 40 y = 315

を標準的な円のequationの形式で書き換える

(x - (- \frac{19}{32}))^{2} + (y - \frac{5}{4})^{2} = (\frac{22121}{32})^{2}

ゆえに円の特性は:

(a, b) = (- \frac{19}{32}, \frac{5}{4}), r = \frac{22121}{32}