de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

2x^{(2)}+2y^{(2)}-4x+12y-12=0

Lösung

2 x^{(2)} + 2 y^{(2)} - 4 x + 12 y - 12 = 0

Lösung

(a, b) = (1, - 3), r = 4

Schritte zur Lösung

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

Rewrite

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 4

Graph

Beliebte Beispiele

(x-8)^2+(y+3)^2=1

(x - 8)^{2} + (y + 3)^{2} = 1

x^2+y^2-4x-12y-6=0

x^{2} + y^{2} - 4 x - 12 y - 6 = 0

x^2+y^2-4y-15=6

x^{2} + y^{2} - 4 y - 15 = 6

(x-5)^2+(y+2)^2-85=0

(x - 5)^{2} + (y + 2)^{2} - 85 = 0

x^2+y^2+4x-3y=9

x^{2} + y^{2} + 4 x - 3 y = 9