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Beliebt Geometry >

(x+4)^2+(y+12)^2-16=0

Lösung

(x + 4)^{2} + (y + 12)^{2} - 16 = 0

Lösung

(a, b) = (- 4, - 12), r = 4

Schritte zur Lösung

(x + 4)^{2} + (y + 12)^{2} - 16 = 0

Rewrite

(x + 4)^{2} + (y + 12)^{2} - 16 = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 12))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 12), r = 4

Graph

Beliebte Beispiele

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