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Beliebt Geometry >

center 4x^2+12x+4y^2+16y-11=0

Lösung

center

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

Lösung

(- \frac{3}{2}, - 2)

Schritte zur Lösung

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

Rewrite

4 x^{2} + 12 x + 4 y^{2} + 16 y - 11 = 0

in the form of the standard circle equation

(x - (- \frac{3}{2}))^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{2}, - 2), r = 3

And the center is:

(- \frac{3}{2}, - 2)

Graph

Beliebte Beispiele

center 100x^2+100y^2-100x+400y+409=0

ce n t er 100 x^{2} + 100 y^{2} - 100 x + 400 y + 409 = 0

center (x^2)/9+(y^2)/9 =1

ce n t er \frac{x ^{2}}{9} + \frac{y ^{2}}{9} = 1

center (x-1/2)^2+(y-1/2)^2= 9/4

ce n t er (x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

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ce n t er x^{2} + y^{2} - 2 x - 4 y - 4 = 0

center 2x^2+2y^2-8=0

ce n t er 2 x^{2} + 2 y^{2} - 8 = 0