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Beliebt Geometry >

center x^2+y^2-4x+2y+4=0

Lösung

center

x^{2} + y^{2} - 4 x + 2 y + 4 = 0

Lösung

(2, - 1)

Schritte zur Lösung

x^{2} + y^{2} - 4 x + 2 y + 4 = 0

Rewrite

x^{2} + y^{2} - 4 x + 2 y + 4 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 1))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (2, - 1), r = 1

And the center is:

(2, - 1)

Graph

Beliebte Beispiele

center (x-3)^2+(y+5)^2=49

ce n t er (x - 3)^{2} + (y + 5)^{2} = 49

center x^2+y^2+14x-16+64=0

ce n t er x^{2} + y^{2} + 14 x - 16 + 64 = 0

center x^2+y^2=21

ce n t er x^{2} + y^{2} = 21

center x^2+y^2-20x+36y+353=0

ce n t er x^{2} + y^{2} - 20 x + 36 y + 353 = 0

center (x+1)^2+(y-5)^2=4

ce n t er (x + 1)^{2} + (y - 5)^{2} = 4