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Beliebt Geometry >

center x^2+y^2+14x+16y+14=0

Lösung

center

x^{2} + y^{2} + 14 x + 16 y + 14 = 0

Lösung

(- 7, - 8)

Schritte zur Lösung

x^{2} + y^{2} + 14 x + 16 y + 14 = 0

Rewrite

x^{2} + y^{2} + 14 x + 16 y + 14 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 8))^{2} = (311)^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 8), r = 311

And the center is:

(- 7, - 8)

Graph

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