3x^2+5x-k(x)=0

解

3 x^{2} + 5 x - k (x) = 0

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}

解答ステップ

3 x^{2} + 5 x - y = 0

3 x^{2} + 5 x - y = 0

を標準的な形式で書き換える

4 \cdot \frac{1}{12} (y - (- \frac{25}{12})) = (x - (- \frac{5}{6}))^{2}

ゆえに放物線の特性は:

(h, k) = (- \frac{5}{6}, - \frac{25}{12}), p = \frac{1}{12}