半径 x^2+y^2-8x+18y+16=0

解答

半径

x^{2} + y^{2} - 8 x + 18 y + 16 = 0

r = 9

求解步骤

x^{2} + y^{2} - 8 x + 18 y + 16 = 0

将

x^{2} + y^{2} - 8 x + 18 y + 16 = 0

改写为圆标准方程

(x - 4)^{2} + (y - (- 9))^{2} = 9^{2}

因此圆的性质是:

(a, b) = (4, - 9), r = 9

半径是:

r = 9

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r a d i u s x^{2} + y^{2} - 14 x - 2 y = 50

r a d i u s 4 (x + 5)^{2} + 4 (y + 4)^{2} - 20 = 0