2x+y^2-y<= 1

Lösung

2 x + y^{2} - y \leq 1

(h, k) = (\frac{5}{8}, \frac{1}{2}), p = - \frac{1}{2}

Schritte zur Lösung

2 x + y^{2} - y \leq 1

Rewrite

2 x + y^{2} - y \leq 1

in the standard form

4 (- \frac{1}{2}) (x - \frac{5}{8}) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{8}, \frac{1}{2}), p = - \frac{1}{2}