x^2-6x-4y+1=0

Lösung

x^{2} - 6 x - 4 y + 1 = 0

(h, k) = (3, - 2), p = 1

Schritte zur Lösung

x^{2} - 6 x - 4 y + 1 = 0

Rewrite

x^{2} - 6 x - 4 y + 1 = 0

in the standard form

4 \cdot 1 \cdot (y - (- 2)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 2), p = 1

2 y^{2} = - 10 x

(y + 9)^{2} + 2 (x - 4) = 0

(x + 9)^{2} - 2 (y - 4) = 0

x + y^{2} = 25

y^{2} = x - 7