gs= 1/2 gt^2

Lösung

g s = \frac{1}{2} g t^{2}

(h, k) = (0, 0), p = \frac{1}{2}

Schritte zur Lösung

g s = \frac{1}{2} g t^{2}

Rewrite

g s = \frac{1}{2} g t^{2}

in the standard form:

4 \cdot \frac{1}{2} (s - 0) = (t - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{2}

3 x^{2} - 4 y = 0

x^{2} - y = 5

(y - (5))^{2} = 2 (x - 1)

x = - 3 y^{2} + 1

x^{2} - 6 y + 2 x - 17 = 0