y^2+x-4=0

Lösung

y^{2} + x - 4 = 0

(h, k) = (4, 0), p = - \frac{1}{4}

Schritte zur Lösung

y^{2} + x - 4 = 0

Rewrite

y^{2} + x - 4 = 0

in the standard form:

4 (- \frac{1}{4}) (x - 4) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (4, 0), p = - \frac{1}{4}

x^{2} = 64 (y - 5)

x^{2} - 20 y = 0

y^{2} = x + 36

2 x^{2} - 5 x = x^{2} + 3 x - k (x) + 1

3 y^{2} - 6 x = 0